
In mathematics, the special linear group
\operatorname{SL}(n,R)
n
R
n x n
1
\det\colon\operatorname{GL}(n,R)\toR x .
where
R x
R
R
0
R
These elements are "special" in that they form an algebraic subvariety of the general linear group – they satisfy a polynomial equation (since the determinant is polynomial in the entries).
When
R
q
\operatorname{SL}(n,q)
The special linear group
\operatorname{SL}(n,\R)
\Rn
See main article: Special linear Lie algebra. When
F
\R
\C
\operatorname{SL}(n,F)
\operatorname{GL}(n,F)
n2-1
ak{sl}(n,F)
\operatorname{SL}(n,F)
n x n
F
Any invertible matrix can be uniquely represented according to the polar decomposition as the product of a unitary matrix and a Hermitian matrix with positive eigenvalues. The determinant of the unitary matrix is on the unit circle, while that of the Hermitian matrix is real and positive. Since in the case of a matrix from the special linear group the product of these two determinants must be 1, then each of them must be 1. Therefore, a special linear matrix can be written as the product of a special unitary matrix (or special orthogonal matrix in the real case) and a positive definite Hermitian matrix (or symmetric matrix in the real case) having determinant 1.
It follows that the topology of the group
\operatorname{SL}(n,\C)
\operatorname{SU}(n)
(n2-1)
\operatorname{SU}(n)
\operatorname{SL}(n,\C)
n\geq2
The topology of
\operatorname{SL}(n,\R)
\operatorname{SL}(n,\R)
\operatorname{SO}(n)
\Z
n=2
\Z2
n>2
\operatorname{SL}(n,\R)
\operatorname{SL}(n,\C)
n>1
See also: Whitehead's lemma.
Two related subgroups, which in some cases coincide with
\operatorname{SL}
\operatorname{SL}
\operatorname{GL}
\operatorname{SL}
[\operatorname{GL},\operatorname{GL}]<\operatorname{SL}
The group generated by transvections is denoted
\operatorname{E}(n,A)
\operatorname{TV}(n,A)
n\geq3
n\geq3
\operatorname{E}(n,A)<[\operatorname{GL}(n,A),\operatorname{GL}(n,A)]
For
n=2
2 x 2
A
F2
A3\cong[\operatorname{GL}(2,F2),\operatorname{GL}(2,F2)]<\operatorname{E}(2,F2)=\operatorname{SL}(2,F2)=\operatorname{GL}(2,F2)\congS3,
A3
S3
However, if
A
A
SK1(A)=\operatorname{SL}(A)/\operatorname{E}(A)
\operatorname{SL}(A)
\operatorname{E}(A)
If working over a ring where
\operatorname{SL}
\operatorname{SL}
\operatorname{GL}
A sufficient set of relations for
SL(n,Z)
n\geq3
Tij:=eij(1)
1
ij
0
i ≠ j
\begin{align} \left[Tij,Tjk\right]&=Tik&&fori ≠ k\\[4pt] \left[Tij,Tk\ell\right]&=1&&fori ≠ \ell,j ≠ k\\[4pt] \left(T12
| -1 | |
| T | |
| 21 |
T12\right)4&=1 \end{align}
are a complete set of relations for
SL(n,Z),n\geq3
In characteristic other than 2, the set of matrices with determinant form another subgroup of GL, with SL as an index 2 subgroup (necessarily normal); in characteristic 2 this is the same as SL. This forms a short exact sequence of groups:
1\to\operatorname{SL}(n,F)\to\operatorname{SL}\pm(n,F)\to\{\pm1\}\to1.
This sequence splits by taking any matrix with determinant, for example the diagonal matrix
(-1,1,...,1).
n=2k+1
-I
\operatorname{SL}\pm(2k+1,F)\cong\operatorname{SL}(2k+1,F) x \{\pmI\}
n=2k
-I
Over the real numbers, has two connected components, corresponding to and another component, which are isomorphic with identification depending on a choice of point (matrix with determinant). In odd dimension these are naturally identified by
-I
The group
\operatorname{GL}(n,F)
F x =\operatorname{GL}(1,F)\to\operatorname{GL}(n,F)
F x
\operatorname{GL}(n,F)
\operatorname{GL}(n,F)
\operatorname{SL}(n,F)
F x
\operatorname{GL}(n,F)=\operatorname{SL}(n,F)\rtimesF x