On 2006-10-12, Pierre Quentel <quentel.pierre at wanadoo.fr> wrote:
>> >>> parseline( 'A 1 22 3 6', 'sdxf')
>> ['A', 1, None, 3.0]
>> Yes, but in this case the OP expects to get ['A',1,3.0]
>> A shorter version :
>> def parseline(line,format):
> xlat = {'x':None,'s':str,'f':float,'d':int,'i':int}
> result = [ xlat[f](w) for f,w in zip(format,line.split())
> if xlat.get(f,None) ]
> if len(result) == 0: return None
> if len(result) == 1: return result[0]
> return result
I don't like the name, since it actually seems to be parsing a
string.
--
Neil Cerutti
